Question 1

What is 19 PSU in mg/L?

Accepted Answer

19 PSU = 18,907.4 mg/L. Use the converter on this page to convert to other salinity / tds units instantly.

Question 2

How do you convert PSU to mg/L?

Accepted Answer

Formula: 1 g/kg ≈ 1.0049 PSU · 1 mg/L ≈ 0.001 PSU · 1 ppm ≈ 0.001 PSU (dilute aqueous approximation). Multiply your PSU value by the appropriate factor to get mg/L, or use the interactive converter above.

Question 3

What is 18,907.4 mg/L in PSU?

Accepted Answer

18,907.4 mg/L = 19 PSU.

PSU	mg/L
16 PSU	15,922
17 PSU	16,917.1
18 PSU	17,912.2
19	18,907.4
20 PSU	19,902.5
21 PSU	20,897.6
22 PSU	21,892.7

19 PSU to mg/L

Formula